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andreev551 [17]
3 years ago
11

What is the product? (-3s+2t)(4s-t)

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

-12s²+11st-2t²

Step-by-step explanation:

(-3s+2t)(4s-t)

=−3s(4s)  −3s(−t)+2t(4s)+2t(−t)

=-12s²+3st+8st-2t²

=-12s²+11st-2t²

Marizza181 [45]3 years ago
5 0

Answer:

12s² + 11st - 2t²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

- 3s(4s - t) + 2t(4s - t) ← distribute both parenthesis

= - 12s³ + 3st + 8st - 2t² ← collect like terms

= - 12s² + 11st - 2t²

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A normal distribution has a standard deviation equal to 39. What is the mean of this normal distribution if the probability of s
Naily [24]

Answer:

The mean is \mu = 131

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\sigma = 39

What is the mean of this normal distribution if the probability of scoring above x = 209 is 0.0228?

This means that when X = 209, Z has a pvalue of 1-0.0228 = 0.9772. So when X = 209, Z = 2.

Z = \frac{X - \mu}{\sigma}

2 = \frac{209 - \mu}{39}

209 - \mu = 2*39

\mu = 209 - 78

\mu = 131

The mean is \mu = 131

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3 years ago
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DanielleElmas [232]
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Step-by-step explanation:

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Step-by-step explanation:

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Simplify for a = 3, b = -4 and c = -1.<br><br> 9−a(c+5)
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