Answer:
<h2>
The eleventh term of the sequence is 64</h2>
Step-by-step explanation:
The sequence given is an arithmetic sequence
14, 19, 24, …………., 264
The nth term of an arithmetic sequence is given as;
Tn = a+(n-1)d where;
a is the first term = 14
d is the common difference = 19-14=24-19 = 5
n is the number of terms = 11(since we are to look for the eleventh term of the sequence)
substituting the given values in the formula given;
T11 = 14+(11-1)*5
T11 = 14+10(5)
T11 = 14+50
T11 = 64
The eleventh term of the sequence is 64
703 rounded to the nearest hundred is 700
Not sure but you can figure it out.
Hello! The solution to this equation does work, because 5 * 3 is 15. When you subtract a negative, you’re actually adding. 15 + 6 is 21. 3 is x and -6 is y. When the values are plugged into the equation, they work.
Answer: 73+.100+.29
Step-by-step explanation: