If 10+9=21 than is 1+1= 2?

Question attached! Please explain how you got them :)

zhannawk [14.2K]

A) Mean - add numbers of animals, and then divide by the number of students.

numbers of animals =1*20+2*11+3*18+4*10+5*3 +6*18 = 259
number of students = 20+20+11+18+10+3+18 = 100
mean=numbers of animals /number of students = 259 / 100=2.59

b) median
You can write 20 zeroes, 20 ones, 11 twos and so on. and the remove from left and right equal amount of number, when you get in the middle,it is going to be median
<u>20 "0", 20 "1", 11 "2"</u>, <u>18 "3", 10 "4", 5 "3", 18 "6"
</u> 51 place 51 place
From the left 20+20+11=51 places
18+5+10+18=51 places
We can see that no single middle number. In the middle is going to be two numbers 2 and 3, and divide them by 2.
(2+3)/2=2.5 median

3) (127/151)*100%≈ 84.11%

8 0

2 years ago

PLEASE ANSWER QUICKLY. WILL GIVE BRAINLIEST IF RIGHT!

vladimir2022 [97]

Answer:

C.

Step-by-step explanation:

That's all I know

4 0

2 years ago

Read 2 more answers

This chart shows the total average monthly cost of medical insurance benefits for employees working in the private sector in mar

marusya05 [52]

It is given in this item that the subject of interest has to pay the single coverage for the medical insurance and is given to be equal to $322.77.

Let x be the number of hours that a person should work in order to pay for the cost of the medical insurance. The value of this variable is calculated by dividing the total insurance cost by the amount that a person earns every hour.

x = $322.77 / ($10/hr)
x = 32.277 hours

Therefore, the number of hours that a person should work is equal to 32.277 which is approximately equal to 32 hours and 17 minutes.

4 0

3 years ago

A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat

zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .