Answer choice A is incorrect as it is missing the variable 'x' in it.
Let's test answer choice B.
y = mx + b
m is the slope
b is the y-intercept
m = 2/3
b = -5
y = (2/3)x - 5
B is one of the answers.
Let's test answer choice C.
6y = 4x -30
y = (4/6)x - 30/6
y = (2/3)x - 5
Answer choice C is also correct.
Let's test answer choice D now.
y = (2/3)x - 5
Plug in (3,-3)
-3 = (2/3)(3) - 5
-3 = 2 - 5
-3 = -3
This is correct, so therefore D is also one of the answers.
Your answer is B, C and D.
Answer:
4^12
Step-by-step explanation:
4^9 * 4^3
We know that a^b * a^c = a^ (b+c)
4^9 * 4^3
4^(9+3)
4^12
Answer:
It would be B
Step-by-step explanation:
Make a table with the angle theta as independent variable and the radius r as dependent variable:
theta radius = 4+2cos theta radius
------- -----------------------------------------
0 4+2 6
pi/6 4+2cos pi/6 = 4+2(sqrt(3)/2
Perhaps you have already plotted this using webassign (but remember that you have not shared an illustration here). (Please don't type "webassign plot" repeatedly, as it accomplishes nothing.)
Generally, when one wishes to find the area of a region defined by polar functions (as is the case here), one first determines suitable limits of integration from the finished curve and checks them through actual integration.
Which formula should you use to find the area: Look up "areas in polar coordinates," as I did. The formula is as follows:
Enclosed area = Integral from alpha to beta of (1/2)r^2 d(theta). Note that the initial radius here is 6 (since r = 4 plus 2 cos theta is 4+2 when theta = 0).
For question one the answer is -1.8
And for question two it's -12.82
