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olga55 [171]
2 years ago
9

Evaluate (98 x 102) by using suitable identities.

Mathematics
2 answers:
GREYUIT [131]2 years ago
8 0

Answer:

The answer is 9996

Step-by-step explanation:

Using the identity (x+a)(x+b) = x  ^2  +(a+b)x+ab

Writing 102 as 100+2 and 98 as 100−2

Hence (100+2)(100−2) = 100  ^2  +[2+(−2)]100+(2)(−2)

= 10000+(0)100−4

= 9996

The answer is 9996

andre [41]2 years ago
3 0

Answer:

9996

Step-by-step explanation:

by using suitable identities ;

  • (98) × (102)
  • (100 - 2) × (100 + 2)
  • 10000 - 4
  • 9996

identity used here is :

(a + b) \times (a - b) = (a {}^{2}  - b {}^{2} )

..........................

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<h3>What is the interquartile range?</h3>

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2 years ago
IM DOING A TEST!<br><br> Idk how to do this help<br> Please try
goldenfox [79]

Answer:

1 is 102

2 is 78

~~~~~~~~~~~~~~~~~~~~

Always double check :)

7 0
3 years ago
Read 2 more answers
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