Answer: The required values are
x = 12 units, ST = 60 units and SU = 120 units.
Step-by-step explanation: Given that T is the midpoint of SU, where
ST = 5x and TU = 3x + 24.
We are to find the values of x, ST and SU.
Since T is the midpoint of SU, so we get

So, the value of x is 12.
Therefore,

and

Thus, the required values are
x = 12 units, ST = 60 units and SU = 120 units.
Answer:
Part 1) The number of cups of flour needed to make 4 pizzas is 26
Part 2) The number of pizzas Luigi can make with 13 cups of flour is 2
Step-by-step explanation:
we know that
Luigi uses 39 cups of flour for every 6 pizzas he makes
Let
y ----> the number of cups of flour used
x ---> the number of pizzas he makes
In this problem
The relationship between the variables x, and y, represent a proportional variation
we have the ordered pair (6,39)
so

Part 1) Find out the number of cups of flour needed to make 4 pizzas
using a proportion

Solve for y


Part 2) Find out the number of pizzas Luigi can make with 13 cups of flour
using a proportion

Solve for x


Answer:
456/12= 38 means 38 kids share a locker
Step-by-step explanation:
This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible = 
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible = 
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible = 
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83
1)
you have similar triangles(ABC, ADE), so their side length ratios are equal
8/2=4/CE
CE*4=4
CE=1
2)
angle bisector theorem:
CD/DA=BC/BA
CD/DA=10/8
I:AD=10CD/8
we also know AC=AD+CD=6
II:CD=6-AD
insert II in I:
AD=10(6-AD)/8
=5(6-AD)/4
=(30-5AD)/4
4AD=30-5AD
9AD=30
3AD=10
AD=10/3