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rjkz [21]
4 years ago
5

Please help me with these questions (It’s due tomorrow)

Mathematics
1 answer:
NISA [10]4 years ago
5 0
A.) x(x-2)
x^2-2

B.) x(x+6)+3(x+6)
x^2+6x+3x+18
x^2+9x+18

C.) (x+3)(x+6)
x^2+6x+3x+18
x^2+9x+18
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Write an equation of a line with the given slope and y-intercept. m = –5, b = –3. A. y = –5x – 3 . B. y = –5x + 3 . C. y = 5x –
True [87]
Y = mx + b
y = -5x -3

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Question 5 (12 points)
Dima020 [189]

Answer:

see attached for diagram

a) √13

b) √29

c) 4

Step-by-step explanation:

Equation of the circle:  (x + 1)^2 + (y - 3)^2 = 16

⇒ center = (-1, 3)

⇒ radius = √16 = 4

Distance between 2 points formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

a)  let (-1, 3) = (x_1,y_1)

    let (2, 1) = (x_2, y_2)

 \implies \sqrt{(2+1)^2+(1-3)^2} =\sqrt{13}

b)  let (-1, 3) = (x_1,y_1)

    let (4, 1) = (x_2, y_2)

\implies \sqrt{(4+1)^2+(1-3)^2} =\sqrt{29}

c)  let (-1, 3) = (x_1,y_1)

    let (3, 3) = (x_2, y_2)

\implies \sqrt{(3+1)^2+(3-3)^2} =4

4 0
3 years ago
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Write an exponential function y = ab" whose graph passes through (2,12) and (5,96).
motikmotik

Answer:

y = 3(2)^{x}

Step-by-step explanation:

Substitute the given points into the function and solve for a and b

Using (2, 12)

12 = ab² → (1)

Using (5, 96)

96 = ab^{5} → (2)

Divide (2) by (1)

\frac{ab^5}{ab^2} = \frac{96}{12} , that is

b³ = 8 ( take the cube root of both sides )

b = \sqrt[3]{8} = 2

Substitute b = 2 into (1) and solve for a

12 = a2² = 4a ( divide both sides by 4 )

3 = a

Thus

y = 3(2)^{x} ← is the exponential function

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Multiply 12 x 12 which is 144. And then you divide that by 6 and you get 24
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