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Nookie1986 [14]
3 years ago
5

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply. 0 = 2x2 – 7x – 9 0 = x2 – 4x + 4 0 = 4x2 – 3x – 1 0 = x2 – 2x – 8 0 = 3x2 + 5x + 3
Mathematics
2 answers:
Andrews [41]3 years ago
5 0

Answer:

A, C, D

Step-by-step explanation:

Took the test

adoni [48]3 years ago
3 0

Step-by-step explanation

<h3>Prerequisites:</h3>

<u>You need to know: </u>

b^2 - 4ac = 0 \Rightarrow 1 solution

b^2 - 4ac > 0 \Rightarrow 2 solutions

b^2 - 4ac < 0 \Rightarrow No\ real\ solutions

----------------------------------------------------------------

2x^2-7x-9 = 0

b^2 - 4ac

-7^2 - 4(2)(-9) = 121

2 Solutions

---------------------------------------------------------------

x^2-4x+4 = 0

b^2 - 4ac

-4^2 - 4(1)(4) = 0

1 Solution

---------------------------------------------------------------

4x^2-3x-1 = 0

b^2 - 4ac

-3^2 - 4(4)(-1) = 25

2 Solutions

---------------------------------------------------------------

x^2-2x-8 = 0

b^2 - 4ac

-2^2 - 4(1)(-8) = 36

2 Solutions

---------------------------------------------------------------

3x^2+5x+3 = 0

b^2 - 4ac

5^2 - 4(3)(3) = -11

No Solutions

---------------------------------------------------------------


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