Question

The points (10, -10) and (8, -10) fall on a particular line. What is its equation in slope-intercept form?

Answer 1

y = 0x - 10 is the equation in slope-intercept form given that the points (10, -10) and (8, -10) which fall on a particular line. This can be obtained by the formula of the slope-intercept form of the line.

What is its equation in slope-intercept form?

• Linear equation is an equation that models a linear function.

In linear equation the variables are raised to the first power.

Example, Linear equation: 2x + 3, Not a linear equation: x² + 5

The graph of a linear equation contains all the ordered pair that are solutions of the equation.

The equation of a line is given by,

y = mx + c, m is the slope of the equation, c is the y intercept

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$,  y intercept is the y coordinate of the point where y crosses the y axis.

Here in the question it is given that,

The points (10, -10) and (8, -10) fall on a particular line.

 

We have to find the equation in slope-intercept form.

Slope of the equation will be,

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ ⇒ m = $\frac{-10 -(-10) }{8 -10 }$ ⇒ m = 0  

y-intercept of the equation will be,

y = mx + c ⇒ -10 = 0 + c ⇒ c = -10

The equation of the line in slope-intercept form will be,

y = 0x -10

Hence y = 0x - 10 is the equation in slope-intercept form given that the points (10, -10) and (8, -10) which fall on a particular line.

Learn more about slope-intercept form here:

brainly.com/question/9682526

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