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ELEN [110]
2 years ago
10

Need help answer plzzzz ​

Mathematics
2 answers:
tatiyna2 years ago
7 0
2n+n+108=180
3n=72
n= 24
dolphi86 [110]2 years ago
5 0

:2n+n+108=180

3n=72

n= 24

Step-by-step explanation: WAIT nvm i got it!!

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Help me i'll help you back
Dmitriy789 [7]

Answer:

A, C, B, respectively

Step-by-step explanation:

science(density and buoyancy)

8 0
3 years ago
Name a pair of overlapping congruent triangles in each diagram. State whether the triangles are congruent by SSS, SAS, ASA, AAS,
MariettaO [177]

Answer:

ΔPTS≅ΔRTA by AAS axiom of congruency

Step-by-step explanation:

Consider ΔPQA and ΔRQS

∠PQA=∠RQS     (Vertically Opposite Angles)

∠QAP=∠QSR     (Complementary of two equal angles, ∠RAT and∠PST)

Due to angle sum property of a triangle, we come to the conclusion that

∠APQ=∠SRQ

Consider ΔPTS and ΔRTA

TA=TS  (Given)

∠RAT=∠PST(Given)

∠APQ=∠SRQ (Proved above)

Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.

8 0
3 years ago
Are the ratios 3:5 and 2:4 equivalent?<br> yes or no
jeyben [28]

Answer:

No, they are not.

Step-by-step explanation:

A ratio can be written as a fraction. So 3:5 is the same as 3/5 and 2:4 is the same as 2/4.

3/5 = 2/4

0.6 = 0.5 INCORRECT

As you can see, the both don't equal the same numbers, so they aren't equivalent.

4 0
2 years ago
Read 2 more answers
Caroline earns $106.25 for 5 hours of work. If she makes a constant hourly wage, which table represents the relationship between
Debora [2.8K]

Answer: A

Step-by-step explanation:

7 0
3 years ago
Need help fast please! Factor by grouping. 6x³ + 24x² -7x -28 =
olchik [2.2K]

Answer:

(x+4)(6x^2 - 7)

Step-by-step explanation:

Focus on the first 2 terms first and on the second 2 terms last:

6x^3 + 24x^2 = 6x^2(x+4)

-7x-28 = -7(x+4)

We see that the factor (x+4) is common to both pairs:  common to the first 2 terms and common to the last 2 terms.

Thus,

6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)

Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).

5 0
3 years ago
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