X^2+5x=2
you then solve by completing the square using the formula (b/2)^2 in order to create the new term. Solve for x by using this term to complete the square.
Your answer is then
x=-5/2+-√33/2
1/6 of 3/4 mile = 1/6 * 3/4 = 1/8 = 0.125 mile
The correct result would be 1/8 or 0.125 mile.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
The midpoint of MN is <u>(7,1)</u>
Add the x coordinates 7+7=14 then you divide that by 2 giving you 7.
Then you add the y coordinates together 6+(-4)=2 then divide by 2 and that gives you 1. Therefore the answer is (7,1)
Answer:
I'm pretty sure it is the second one
Step-by-step explanation:
