Choose the equation of the line that contains the point (1,-1) and (2,-2)

Geometry help?<br> 24/10<br> 10/24<br> 24/26<br> 10/26

olasank [31]

24/26 or opposite over adjacent. The answer is C

8 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

Evaluate the expression 4⋅f(6)−6⋅g(5)

sladkih [1.3K]

Answer:

send full question

Step-by-step explanation:

4 0

3 years ago

Malia and her sister watched an action movie that was 2 hours and 5 minutes long. After

Black_prince [1.1K]

Answer: they started at 1:10 pm

7 0

3 years ago

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Expand quadratic equation (2x-3)(x+4) = 0

OleMash [197]

Answer:

Step-by-step explanation:

Simplifying

(2x + -3)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(-4 + x) = 0

Multiply (-3 + 2x) * (-4 + x)

(-3(-4 + x) + 2x * (-4 + x)) = 0

((-4 * -3 + x * -3) + 2x * (-4 + x)) = 0

((12 + -3x) + 2x * (-4 + x)) = 0

(12 + -3x + (-4 * 2x + x * 2x)) = 0

(12 + -3x + (-8x + 2x2)) = 0

Combine like terms: -3x + -8x = -11x

(12 + -11x + 2x2) = 0

Solving

12 + -11x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.

(3 + -2x)(4 + -1x) = 0

Subproblem 1

Set the factor '(3 + -2x)' equal to zero and attempt to solve:

Simplifying

3 + -2x = 0

Solving

3 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.

3 + -3 + -2x = 0 + -3

Combine like terms: 3 + -3 = 0

0 + -2x = 0 + -3

-2x = 0 + -3

Combine like terms: 0 + -3 = -3

-2x = -3

Divide each side by '-2'.

x = 1.5

Simplifying

x = 1.5

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying

4 + -1x = 0

Solving

4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0

0 + -1x = 0 + -4

-1x = 0 + -4

Combine like terms: 0 + -4 = -4

-1x = -4

Divide each side by '-1'.

x = 4

Simplifying

x = 4

Solution

x = {1.5, 4}

6 0

3 years ago

Read 2 more answers