1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
Answer:
Step-by-step explanation:
Answer:
9:30 am
Step-by-step explanation:
We can make a chart and keep filling it in until we see the same time in both columns.
Bus A Bus B
7:00 7:00
7:30 7:50
8:00 8:40
8:30 9:30
9:00 10:20
9:30
Answer: 9:30 am
We can also use the least common multiple of 30 and 50.
We need to find the smallest number that is a multiple of both 30 and 50.
30 = 2 * 3 * 5
50 = 2 * 5^2
LCD = 2 * 3 * 5^2 = 150
The first time the buses will be at the depot together after 7:00 am is 150 minutes later. 150 minutes = 2 hours 30 minutes.
7:00 am + 2 hours and 30 minutes = 9:30 am
Answer: 9:30 am
Answer:
Not enough information given. Please type the whole question out.
