A rectangular prism is a cuboid so volume of cuboid is base area x height which is 5x5x12=300
volume of pyramid is 1/3 x base area x height = 5x5x6x1/3=50 thus volume outside pyramid and inside cuboid is 300-50=250
Answer:
b^-6
Step-by-step explanation:
(b^-2) / (b^4) = b^(-2 - 4)
There are 2.54 cm in 1 inch. Since we are estimating, we can round the average growth per year to .5 cm which would give you roughly 5 years per inch of diameter (2.5 / .5 = 5). Since we have a tree with a 4 inch diameter, we can estimate the age of the tree is...
4 inches x 5 years/inch = 20 years old.
Answer:
D.) It has rotational symmetry with an angle of rotation of 90 degrees.
Step-by-step explanation:
i) the shape shown in the figure has reflectional symmetry with four lines of symmetry. There are four lines of symmetry such that each line when drawn divides the shape into two exact halves such that if each half were too be folded across the line of symmetry it would produce the other half exactly.
Therefore Option A.) and Option B.) are not true
ii) It has point symmetry which means if the shape is rotated by 180 degrees the shape does not change. Therefore Option C.) is not true.
iii) the shape has rotational symmetry because if the shape is rotated though any between 0 degrees and 360 degrees the shape appears to be unchanged.
Therefore the correct options are
D.) It has rotational symmetry with an angle of rotation of 90 degrees.
Answer: 3.712 hours or more
Step-by-step explanation:
Let X be the random variable that denotes the time required to complete a product.
X is normally distributed.
Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.
Then, 
![P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]](https://tex.z-dn.net/?f=P%28z%3E%5Cdfrac%7Bx-3.2%7D%7B%5Csigma%7D%29%3D0.10%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D)
As, 
[By z-table]
Then,
So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.
