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PolarNik [594]
3 years ago
12

4/5 to 3/5 as a tenth of a percent

Mathematics
1 answer:
Rudik [331]3 years ago
5 0
12/25 that will be the answer so its the percent time always helps.
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Use the circle to represent the following situation and show how you came up with the answer.
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Answer:

look below bestie

Step-by-step explanation:

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Someone help me with the ASAP!
JulsSmile [24]

\mathsf{Given :\;\;\dfrac{12}{\frac{3}{5}}}

\mathsf{:\implies 12 \times \dfrac{5}{3}}

\mathsf{:\implies 4 \times 5}

\mathsf{:\implies 20}

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Madison saves 40% of all that she earns for washing cars. So far she has saved $72 . How much has she earned in all?
UkoKoshka [18]

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Your neighbor will pay you $9.00 to wash his car. How many full hours will you now have to babysit (at $10.00 an hour) so you ca
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Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
3 years ago
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