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3 years ago

The smaller rectangle is a 1/2 scale drawing of the original figure.

Mathematics

2 answers:

Anton [14]3 years ago

8 0

Since the smaller rectangle is a 1/2 scale drawing of the original figure, you may either multiply the measurements of the original figure by 1/2 or divide the measurements of the original figure by 2. Then, to find the area, multiply the length times the width.

Length: 36/2 = 18 cm
Width: 28/2 = 14 cm
Area: 18 * 14 = 252 cm²

Hope this helps! :)

seraphim [82]3 years ago

6 0

The scale of the smaller rectangle is 1/2 of the larger.

Divide each measurements by 2

36/2 = 18
length = 18 cm

28/2 = 14
width = 14 cm

A = length x width
A = 18 x 14
A = 252 cm²

hope this helps

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Read 2 more answers

A metallurgist has an alloy with 5

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$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.30y\\
-----&-----&-------&-------\\
mixture&100&0.15&(100)(0.15)
\end{array}$

so hmm notice, we use the decimal format for the percent, namely 15% is just 15/100 and 5% is just 5/100 and so on

whatever the amounts of "x" and "y" are, they must add up to 100 grams
thus x + y = 100

and whatever the concentrated amounts are, they'll add up to (100)(0.15)

thus $\bf \begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.30y=(100)(0.15)\\
----------\\
0.05x+0.30\left( \boxed{100-x} \right)=(100)(0.15)
\end{cases}$

solve for "x", to see how much 5% alloy will be needed

what about "y"? well y = 100 -x

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