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notka56 [123]
3 years ago
13

Volume = 4,410 yd 30 yd radius =

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

Radius = 11.85yd

Step-by-step explanation:

Volume of a Cone formula: V = πr²(h/3)

We know that;

V = Volume

r = radius

π = pi (this is a sign located on your calculator)

h = height

We are given that;

V = 4,410

r = unknown

h = 30

Let's substitute the values in:

=> V = πr²(h/3)

=> 4,410 = πr²(30/3)

=> 4,410 = πr²(10)

=> 4,410 / 10 = πr²

=> 441 = πr²

=> 441 / π = r²

=> 140.37 = r²

=> \sqrt{140.37} = r

=> 11.85 = r

Therefore, <u>the radius of the cone = 11.85yd</u>

Hope this helps!

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Solve the given problem. Zara is six years older than half Gary’s age. If Gary is four years old, how old is Zara?
ch4aika [34]

The answer is C. 8

4/2 = 2

2+6 = 8

Let me know if you have any questions!

7 0
3 years ago
If 1900 square centimeters of material are available to make a box with a square base and an open top, find the largest possible
Evgen [1.6K]

Answer:

Volume = 7969 cubic centimeter

Step-by-step explanation:

Let the length of each side of the base of the box  be A and the height of the box be H.

Area of material required to make the box  is equal to  is A^2 + 4*A*H.

A^2 + 4*A*H = 1900

 Rearranging the above equation, we get -  

`H = \frac{(1900 - A^2)}{(4*A)}

Volume of box is equal to product of base area of box and the height of the box -  

V = A*A* H

Substituting the given area we get -

\frac{A^2*(1900 - A^2)}{4A} = \frac{(1900*A - A^3)}{4}

For maximum volume

\frac{dV}{dA} =0

\frac{ 1900}{4} - \frac{3*A^2}{4} = 0

A^2 = \frac{1900}{3}

Volume of the box

= \frac{\frac{1900}{3}*(1900 - \frac{1900}{3}) }{4 * \sqrt{\frac{1900}{3} } }

= 7969 cubic centimeter

3 0
3 years ago
Where is the horizontal center of mass of the entire upper extremity?
mixas84 [53]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
Simplify <br> -4x+2x2-x2+5-3x
Serga [27]

Answer:

9 - 7x - x²

Step-by-step explanation:

-4x+2x2-x²+5-3x = -4x-3x+2x2+5-x²

I arranged the like terms together so it is easier to do the calculations.

-4x-3x+2x2+5-x² = -7x+4+5-x²

Simplify.

-7x+4+5-x² = 9-7x-x²

3 0
3 years ago
Read 2 more answers
Given that it was less than 80º on a given day, what is the probability that it also rained that day? 0.3 0.35 0.65 0.7
eimsori [14]

The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.

<h3>What is probability?</h3>

The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.

The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.

So, This number is 0.30.

Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.

To learn more about the probability from the given link:

brainly.com/question/18638636

The above question is incomplete.

The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?

#SPJ4

7 0
2 years ago
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