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pashok25 [27]
3 years ago
9

-3 1/2 x + 3.5 - x + 6.25

Mathematics
2 answers:
Zolol [24]3 years ago
8 0
The answer to the question is C
soldier1979 [14.2K]3 years ago
7 0

Answer:

C- -24x - 2.75

Step-by-step explanation:

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jasenka [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Solve for w <br> p=2(l+w)
umka2103 [35]

p = 2(l+w)

divide by 2

p/2 = l+w

subtract l from both sides

p/2 - l = 2

Choice c

8 0
3 years ago
WILL MARK BRAINLIEST
Sergeeva-Olga [200]

Answer:

a.$167.03

Step-by-step explanation:

6 0
2 years ago
Please help :( can you explain and write the answer
GrogVix [38]

Answer:

f(x)=x-2

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (−∞,∞),x|x ∈R}(-∞,∞),{x|x ∈R}

Range: (−∞,∞),{y|y∈R}

g(x)=x^2-3x+2

Domain: (−∞,∞),{x|x ∈R}(-∞,∞),{x|x ∈R}

Range: [−1/4,∞),{y∣y≥−1/4}

3 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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