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4 years ago

Which statement must be true?

Mathematics

1 answer:

rosijanka [135]4 years ago

3 0

Answer: A is the correct answer

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By what factor is the volume of a right square pyramid multiplied if its height is multiplied by 8 but the dimensions of its bas

xeze [42]

We have that
the volume of a right square pyramid ---------- > (1/3)b²h

Let
V1------------ > initial volume
V1=(1/3)b²h

<span>if its height is multiplied by 8
</span>
V2=(1/3)b²(8h)-------------- > V2=V1*8

therefore

the answer is the option D

the factor is is 8

5 0

3 years ago

If degree of a polynomial ab³c²

adell [148]

Step-by-step explanation:

zero ...................

4 0

3 years ago

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2. CTfastrak bus waiting times are uniformly distributed from zero to 20 minutes. Find the probability that a randomly selected

Juliette [100K]

Answer:

b. 0.25

c. 0.05

d. 0.05

e. 0.25

Step-by-step explanation:

if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

$P(x)=\frac{1}{b-a}=\frac{1}{20-0} =0.05$

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

$P(X$

Then, the probability that a randomly selected passenger will wait:

b. Between 5 and 10 minutes.

$P(5$

c. Exactly 7.5922 minutes

$P(7.5922)=0.05$

d. Exactly 5 minutes

$P(5)=0.05$

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

$P(15$

6 0

3 years ago

Plz help in solving these 2 questions with steps and explanation!!

fomenos

Answer:

$\large\boxed{Q1:\ x=2\ or\ x=5}\\\boxed{Q2:\ x=1-\sqrt{21}\ or\ x=1+\sqrt{21}}$

Step-by-step explanation:

$\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\text{If}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================$

$\bold{Q1}\\\\x^2-7x+10=0\\\\a=1,\ b=-7,\ c=10\\\\b^2-4ac=(-7)^2-4(1)(10)=49-40=9>0\\\\\sqrt{b^2-4ac}=\sqrt9=3\\\\x_1=\dfrac{-(-7)-3}{2(1)}=\dfrac{7-3}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{-(-7)+3}{2(1)}=\dfrac{7+3}{2}=\dfrac{10}{2}=5\\\\========================================$

$\bold{Q2}\\x^2-2x=20\qquad\text{subtract 20 from both sides}\\\\x^2-2x-20=0\\\\a=1,\ b=-2,\ c=-20\\\\b^2-4ac=(-2)^2-4(1)(-20)=4+80=84>0\\\\\sqrt{b^2-4ac}=\sqrt{84}=\sqrt{4\cdot21}=\sqrt4\cdot\sqrt{21}=2\sqrt{21}\\\\x_1=\dfrac{-(-2)-2\sqrt{21}}{2(1)}=\dfrac{2-2\sqrt{21}}{2}=1-\sqrt{21}\\\\x_2=\dfrac{-(-2)+2\sqrt{21}}{2(1)}=\dfrac{2+2\sqrt{21}}{2}=1+\sqrt{21}$

3 0

4 years ago

Read 2 more answers

If f(x) = x–5 and 1/2f(a)=3,then a =...........

Bess [88]

I think it is 6 but im not sure

3 0

3 years ago