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tia_tia [17]
3 years ago
11

Which statement must be true?

Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

Answer: A is the correct answer

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Hannah's monthly housing budget is $1,750. Her monthly costs are $230 for insurance, $98 for utilities, and $250 for taxes. Whic
Olegator [25]
She can afford t he $98
7 0
3 years ago
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Given the quadratic function f(x) = 2x + 5x-12, what is the value of f(-2)?
tino4ka555 [31]

Answer:

-26

Step-by-step explanation:

first substitute -2 for x : 2(-2)+5(-2)-12

-4+-10-12

-14-12

-26

-26 is your answer

pls mark me brainliest if this helps !

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3 years ago
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Simplify the expression <br> y^12/y^12
andreev551 [17]

Step-by-step explanation:

________________________________

Step 1:

\frac{{y}^{12} }{ {y}^{12} }

Wright the equation

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Step 2:

{y}^{12 - 12}

Transfer the power of y ie ¹² up to subtract it

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Step 3:

{y}^{0}

by subtracting the powers we get 0

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Step 4:

1

so the results comes 1 because anything ⁰=1

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⚡Final answer :1✓

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hope it helped you:)

5 0
3 years ago
What is the domain and range of the following function
mel-nik [20]

Answer:

domain: (–∞,∞)    or  all real numbers

range: (–∞,∞)       or  all real numbers

Step-by-step explanation:

domain is left to right (x-axis). looking at the graph, as you go from left to right, the x-values are infinitely getting more negative and positive.

range is bottom to top (y-axis). as you go from bottom to top, the y-values are infinitely getting more negative and positive.

6 0
3 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
Hitman42 [59]

Answer:

The 95% confidence interval = (98.225, 98.655)

Step-by-step explanation:

The formula for Confidence Interval =

Mean ± z × standard deviation/√n

Where Mean = 98.44°F

Standard deviation = 0.30°F

n = number of samples is 10

Because our number if samples is small, we use the t score confidence interval formula

Mean ± t × standard deviation/√n

Degrees of Freedom = n - 1

= 10 - 1 = 9

We find the t score of 95% confidence interval and degrees of freedom 9

= 2.262

Hence,

Confidence interval = 98.44 ± 2.262 × 0.30/√10

= 98.44 ± 0.214592162

Confidence Interval

98.44 - 0.214592162

= 98.225407838

≈ 98.225

98.44 + 0.214592162

= 98.654592162

≈ 98.655

The 95% confidence interval = (98.225, 98.655)

5 0
3 years ago
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