Answer:
90 degree rotation in the clockwise direction.
Step-by-step explanation:
Point A transforms to A'
- that is x coordinate: 2 ---> 3
and y coordinate 3 ---> -2
So the rotation is clockwise from Quadrant1 to Quadrant 4.
The slope of OA = 3/2 and the slope of OA' = -2/3.
The product of these slopes = 3/2 * -2/3 = -1 so the lines are perpendicular - that is the line has passed through an angle of 90 degrees.
A similar result occurs if we consider points B, C and D.
Answer:
x + 5
Step-by-step explanation:
This is actually rather simple to figure out. Simply divide 6x + 30 by 6. That should get x + 5 for the length of one side.
I think #4 is 4 but I'm not completely sure
Answer:
The answer is the first option I hope it helps
Y = -4x + 2
3x + 2y = 6 (or in y-intercept form y=-3/2x + 3)
2x - y = 7 equals y = 2x -7 in y-intercept form. This means that the line has a positive slope and therefore goes upwards. This cannot be a potential equation because the line shown is clearly pointing downwards.
y=5 indicates that the line is a horizontal line that neither points upwards or downwards. This cannot be a potential equation because the line is pointing downwards.
The only possible equations left are y= -4x + 2 and 3x + 2y = 6, both of which graph a line pointing downwards because their slopes are negative. Hope this helps!
