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Alexandra [31]
3 years ago
13

Expand 1/5(10x-25) Whats the ans. Need help.

Mathematics
2 answers:
Inga [223]3 years ago
7 0
I got 2x-5 as an answer.
Vlad1618 [11]3 years ago
7 0
The answers would be 2x-5.
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Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths
storchak [24]

Answer:

15 x = 6.60

x = 44\ hundredths

Step-by-step explanation:

Given

\frac{6.60}{15}

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

\frac{6.60}{15}

Equate to x

x = \frac{6.60}{15}

Multiply both sides by 15

15 * x = \frac{6.60}{15} * 15

15 * x = 6.60

15 x = 6.60

So, we have:

[ ] x = 6.60 =====> 15 x = 6.60

Recall that:

x = \frac{6.60}{15}

x = 0.44

This implies that:

x = 44\ hundredths

Hence:

x = _ hundredths =====> x = 44\ hundredths

3 0
3 years ago
For the given table of values for a polynomial function, where must the zeros of the function lie?
Jet001 [13]

Answer:

A. Between 3.0 and 3.5 and between 4.0 and 4.5

Step-by-step explanation:

The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either f(x) goes from a negative value to a positive value or vice versa.

From x=3.0 and x=3.5, the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.

From x=4.0 and x=4.5, the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.

Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.

7 0
3 years ago
PLSSS HELP ASAPPP I'LL GIVE YOU BRAINLIEST IF I GET IT RIGHT!!!​
kondor19780726 [428]

Answer:

D. 76

Step-by-step explanation:

because students that has 5 absences and less most likely to get higher than 75 marks. The student who has 8 absences studied at home, he's a genius

3 0
3 years ago
Linear or nonlinear​
Wittaler [7]

Answer:

Linear

Step-by-step explanation:

It increases by a steady rate, so it is linear.

5 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
3 years ago
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