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4 years ago

I need help finding surface area for both of these shapes with work

Mathematics

2 answers:

Alex73 [517]4 years ago

7 0

For the base of the shape all you need to do is multiply 25x25=625ft²

then for the 4 sides you need to multiply 25x32=800ft²

and because there are 4 sides you multiply 800x4=3200

so now you add 3200 with 625 (3825) and there's your area

liubo4ka [24]4 years ago

4 0

Nice, so 4 triangles
1 square base (length=width=25)

area triangle=1/2 times base time height
the height is 32
and base is 25
4 of them so
4*1/2*25*32
2*25*32
1600 is triangles

base is 25*25=625

add to find tiatl
1600+625=2225 square feet

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64 fish

Step-by-step explanation:

If there is 1/4 fish with black stripes and its a total of 16 then you have to multiple 16 times 4 because theres 4 groups. so 16 times 4 is 64.

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A rectangular plot of land is 100 feet long and 50 feet wide. how long is the walkway along the diagonal? round to the nearest f

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Answer:

c. 112 ft

Step-by-step explanation:

the diagonal of a rectangle creates a right-angled triangle with a length and a width of the rectangle (the diagonal is the Hypotenuse or baseline).

and this means we can use Pythagoras :

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A particular brand of dishwasher soap is sold in three sizes: 25 oz, 45 oz, and 60 oz. Twenty percent of all purchasers select a

Verdich [7]

Answer:

(a) <u>Sampling distribution </u>

P(25) = 0,04

P(35) = 0.1 + 0.1 = 0,2

P(42,5) = 0.06 + 0.06 = 0,12

P(45) = 0,25

P(52,5) = 0.15 + 0.15 = 0,3

P(60) = 0,09

(b) E(X) = 45.5 oz

Step-by-step explanation:

The variable we want to compute is

$X=(X1+X2)/2$

For this we need to know all the possible combinations of X1 and X2 and the probability associated with them.

(a) <u>Sampling distribution </u>

Calculating all the 9 combinations (3 repeated, so we end up with 6 unique combinations):

P(25) = P(X1=25) * P(X2=25) = p25*p25 = 0.2 * 0.2 = 0,04

P(35) = p25*p45+p45*p25 = 0.2*0.5 + 0.5*0.2 = 0.1 + 0.1 = 0,2

P(42,5) = p25*p60 + p60*p25 = 0.2*0.3 + 0.3*0.2 = 0.06 + 0.06 = 0,12

P(45) = p45*p45 = 0.5 * 0.5 = 0,25

P(52,5) = p45*p60 + p60*p45 = 0.5*0.3 + 0.3*0.5 = 0.15 + 0.15 = 0,3

P(60) = p60*p60 = 0.3*0.3 = 0,09

(b) Using the sample distribution, E(X) can be expressed as:

$E(X)=\sum_{i=1}^{6}P_{i}*X_{i}\\E(X)=0.04*25+0.2*35+0.12*42.5+0.3*52.5+0.09*60 = 45.5$

The value of E(X) is 45.5 oz.

$\mu=\sum_{i=1}^{3}P_{i}*X_{i}\\\mu=0.2*25+0.5*45+0.3*60=45.5$

We can conclude that E(X)=μ

We could have arrived to this conclusion by applying

$E(X)=E((X1+X2)/2)=E(X1)/2+E(X2)/2\\\\\mu = E(X1)=E(X2)\\\\E(X)=\mu /2+ \mu /2 = \mu$

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4 years ago

Transformations of exponential functions

AURORKA [14]

Answer:

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3 years ago