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yKpoI14uk [10]
3 years ago
12

Transformations of exponential functions

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

It's the last one. We know it's to the right because the -8 is in the exponent and also, it's -8 not +8.

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3 years ago
Simplify <br> 1+sinx/cosx+cosx/1+sinx
Dmitry [639]
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
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2sec(x)
6 0
3 years ago
Solve system by elimination <br> 8x-8y=-16<br> -8x-7y=-29
Gnesinka [82]
Add these together.
You get -15y=-45
So y=3

Now plug in to first equation.
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Check both values in second equation.
-8(1)-7(3)=
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6 0
3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

bc ez ez e yba better then aut

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