Answer:
9:6
Step-by-step explanation:
You can find x by setting the ratios equal to each other.

Now you just need to solve for x.

The ratio is 9:6.
to get the slope of any line, all we need is two points off of it, so let's get the slope and thus its equation, hmmmm let's see points (-2,-3) and the origin are the obvious ones =)
![\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-3)}{0-(-2)}\implies \cfrac{0+3}{0+2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-3)=\cfrac{3}{2}[x-(-2)]\implies y+3=\cfrac{3}{2}(x+2) \\\\\\ y+3=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-2%7D~%2C~%5Cstackrel%7By_1%7D%7B-3%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B0%7D~%2C~%5Cstackrel%7By_2%7D%7B0%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B0-%28-3%29%7D%7B0-%28-2%29%7D%5Cimplies%20%5Ccfrac%7B0%2B3%7D%7B0%2B2%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%28-3%29%3D%5Ccfrac%7B3%7D%7B2%7D%5Bx-%28-2%29%5D%5Cimplies%20y%2B3%3D%5Ccfrac%7B3%7D%7B2%7D%28x%2B2%29%20%5C%5C%5C%5C%5C%5C%20y%2B3%3D%5Ccfrac%7B3%7D%7B2%7Dx%2B3%5Cimplies%20y%3D%5Ccfrac%7B3%7D%7B2%7Dx)
Answer:
Answer:
For converging lens
object distance u = - 2.0cm
Focal length f = 5.0cm
From lens formula
m=
m=
=3
Size of image = size of object x Magnification
= 2 x .10 = 2.0cm
For diverging lens
object distance u = 140 - 120 = 20 cm
focal length f = -30 cm
frac{1}{v}+\frac{1}{20}=-\frac{1}{30}
v = -12 cm
m = 12/20 = 0.6
size of final image = .6 x 30 = 18 cm
I THINK there is a typo. Instead of "for problems each day", i think it's "four problems each day."
Anyway, we need to find how many days it takes Jeremy to complete the paper.
If he completes 8 problems on the first day and 4 on the rest of the days, after the first day he'll have 28 - 8 = 20 more problems.
And since he does 4 every day with 20 problems: 20 / 4 = 5 days.
There are 100 squares in the grid.
63 are shaded.
Number of squares shaded is the numerator (number on top of the decimal).
Total number of squares is the denominator (number at the bottom of the decimal).

Whenever the denominator of the fraction is 100, you can just take the numerator and put a decimal behind the number.
Therefore, the decimal represented would be 0.63.