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3 years ago

Carbon is one of the most common elements found in living things

Chemistry

1 answer:

zzz [600]3 years ago

4 0

Answer:

Major Elements

The six most common elements inliving things are carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur. Atoms of these elementscombine and form thousands of large molecules. These large molecules make up the structures of cells and carry out many processes essential to life.

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How does the solubility of a gas change with decreasing temperature? A. It increases. B. It decreases. C. It is uniform. D. Temp

vitfil [10]

A it increases is the correct answer.

Good luck and I hope this helps.!

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3 years ago

Give the word and chemical equations (including state symbols) for the reaction of potassium and water

zepelin [54]

Answer:

Zinc is Zn and Magnesium is Mg

7 0

3 years ago

Someone please help will mark as brainliest

wariber [46]

1. solute is the substance that is being dissolve,while solvent is dissolving medium

2.saturated is solution that contain maximum amount of solut that capable of being dissolve and supersaturated is solution that contain less amount or medium of solut that capable being dissolve : example vinger

3. is a number placed in front of a chemical symbol or formula. It shows how many atoms or molecules of the substance are involved in the reaction. For example, two molecules of hydrogen would be written as 2 H2, and two molecules of water would be written 2 H2O . yes it's can be change only in caseWhen you balance an equation you can only change the coefficients

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3 years ago

A calorimeter holds 125 g water at 22.0°C. A 45 g sample of silver at 130.0°C is added to the water, and the final temperature o

Komok [63]

Answer:

Explanation:

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3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I 2.00 0 0

C -2x +x +x

E 2.00 - 2x x x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

$Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852$

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0

3 years ago