Always convert to moles when comparing compounds.
Molar mass of a compound is the sum of it's atomic molar mass units.
Mg = 24.3 g/mol Mg
O2 = 16 + 16 = 32 g/mol O2
MgO = 24.3 + 16 = 40.3 g/mol MgO
Determine the moles of each reactant/product.
2.2 g Mg * (1 mol/24.3 g Mg) = 0.09 mol Mg
3.6 O2 * (1 mol/32 g O2) = 0.1125 mol O2
2.7 g MgO * (1 mol/40.3 g MgO) = 0.067 mol MgO
Check if there's a limiting reagent. For every 1 O2 we need 2 Mg
0.1125 mol O2 * 2 = 0.225 mol Mg needed.
So Mg is a limiting reagent. We have plenty of O2 which is typically the case when oxygen is a reactant.
Figure out how much product should form based on the moles of limiting reagent. For every 2 Mg 2 MgO are formed. So it's a 1:1 ratio.
0.09 mol Mg ---> 0.09 mol MgO
compare the expected 0.09 mol MgO to the actual 0.067 mol MgO obtained. Calculate the percent obtained.
(0.067 mol MgO obtained) / (0.09 mol MgO expected) * 100 = 74.44 % yield
Answer:
Explanation:
Hello,
In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:
Best regards.
Answer:
Explanation:
The two requirements for a measurement are a <u>number</u> and a <u>unit.</u>
For example, here is a measurement:
38.6 cm
The <u>number</u> is 38.6 and the <u>unit</u> is cm, or centimeters.
Therefore, both <em>number </em>and <em>unit</em> are correct.
Answer:
false
Explanation:
As we know that in sodium-potassium pump .
sodium potassium move 3Na+ outside the cells
and moving 2k+ inside the cells
so that we can say that given statement is false
Answer FALSE