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Helga [31]
3 years ago
11

Simplest form of the expression -2x2(x – 5) + x(2x2 – 10x) + x is

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0
You first simplify the expression using PEMDAS
-2x^3-10x^2+2x^3-10x^2+x
then combine like terms,
(-2x^3+2x^3), (-10x^2-10x^2), x
cancels out^
so the answer would be -20x^2+x
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3x+2y=10<br> 12x+5y=25<br><br> Solve by substitution or elimination
zaharov [31]
3x + 2y = 10 ....multiply by -4
12x + 5y = 25
-------------------
-12x - 8y = -40 (result of multiplying by -4)
12x + 5y = 25
------------------add
-3y = - 15
y = -15/-3
y = 5

3x + 2y = 10
3x + 2(5) = 10
3x + 10 = 10
3x = 10 - 10
3x = 0
x = 0

solution is (0,5)
5 0
3 years ago
Which is the equation of a line that passes through (1,8) and (6,4)
Sati [7]

Answer:

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5}<em> </em>

Step-by-step explanation:

(6, 4)

(1, 8)

m = \frac{8-4}{1-6} = - \frac{4}{5}

y - 4 = - \frac{4}{5} ( x - 6 )

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5} ⇔ y = - 0.8x + 8.8

8 0
2 years ago
Given that BD is the median of AABC and that AABC is isosceles, congruence postulate SSS can be used to prove which of the follo
marusya05 [52]

Answer:

B.

Step-by-step explanation:

Because of isosceles triangle, AB = CB.

Because of the median, AD = CD.

Because of congruence of segments being reflexive, BD = BD.

By SSS, the triangles BAD and BCD are congruent.

Answer: B.

7 0
2 years ago
Under the best conditions, a sprout has a 40% probability of blooming.if two sprouts are selected at random, what is the probabi
Minchanka [31]
The answer is 16 % :D 
5 0
2 years ago
Read 2 more answers
The number of flaws per square yard in a type of carpet material varies with mean 1.4 flaws per square yard and standard deviati
oksian1 [2.3K]
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:
\frac{\sigma}{ \sqrt{n} }=\frac{1.2}{ \sqrt{178} }=0.09
The z-score for 1.5 flaws per square yard is:
z=\frac{1.5-1.4}{0.09}=1.11
The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.
6 0
3 years ago
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