Answer:
163.2 cubic millimeters (or) 163.2 mm^3
Step-by-step explanation:
Given: Radius of cone= 6mm
Height of cone= 4mm
π= 3.14(Approximately)
Required: Volume(V)
Volume of cone= 1/3* π* r^2 * h
Volume= 1/3* (3.14) * (6 m)^2 * (4m)
= 1/3* (3.14) * (36) * (4)
= 163.2 mm^3
Therefore, the Volume of the cone is 163.2 mm^3 (to the nearest tenth) :)
9514 1404 393
Explanation:
The quadrilateral will be a parallelogram if the diagonals bisect each other. That will be the case if the sums of their end-point coordinates are the same.
A + C = (-3, 6) +(9, -9) = (6, -3)
B + D = (6, 0) +(0, -3) = (6, -3)
Both diagonals have their midpoint at (3, -1.5), so the diagonals are mutual bisectors. The figure ABCD must be a parallelogram.
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The midpoint of AC is (A+C)/2 = (6, -3)/2 = (3, -1.5).
Given equation is 
If we substitute x = 0, then, y = - 4.
So, (0, -4) is a point on the line.
If we substitute x = - 6, then y = 5 - 4 = 1.
So, (-6, 1) is another point on the line.
Joining (0, -4) and (-6, 1), we get the graph of the line.
Answer:
J'(2, 1)
K'(0, 3)
Step-by-step explanation:
On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.
If we reflect these points over the line x = 0 or y-axis, rule to be followed is
(x, y) → (-x, y)
Only sign of x coordinates get changed while y coordinates remain the same.
Following this rule coordinates of the images of J' and K' will be
J(-2, 1) → J'(2, 1)
and K(0, 3) → K'(0, 3)