There are 3636 chocolates in a box, all identically shaped. There 1212 are filled with nuts, 99 with caramel, and 1515 are so
lid chocolate. Someone randomly selects one piece, eats it, and then selects a second piece. Find the probability of selecting 2 nut candies. Express your answer as a simplified fraction
In the beginning, the probability to pick a nut piece is 1212/3636. Once you eat it you have 3635 candies left, of which 1211 are nuts, and therefore the probability to pick nut again is 1211/3635.
So, the combined probability is 1212/3636 * 1211/3635 = 1/3 * 1211/3635 = 1211/(3*3635) = 1211/10905
