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Zarrin [17]
3 years ago
6

Write an inequality that represents the statement “x is at most –5 or at least 7.” A. x < –5 or x > 7 B. x > –5 or x &l

t; 7 C. x ≤ -5 or x ≥ 7 D. x ≥ -5 or x ≤ 7
Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0
<span>C. x ≤ -5 or x ≥ 7 D.</span>
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Si el perímetro de el siguiente paralelogramo mide 80 M cuanto mide la base cuanto mide la altura y cuanto mide el área
topjm [15]

Answer:

<h2>The area of the parallelogram is 300 square meters. Its height (length) is 30 meters and its width is 10 meters.</h2>

Step-by-step explanation:

Assuming that the parallelogram is a rectangle, its perimeter would be defined as

P=2(w+l)

Where w is the width and l is the length.

But, P=80 \ m, so

80=2(w+l)\\w+l=40

Which means the sum of its dimensions is 40 meters.

Easily, its dimenions can be 10 meters and 30 meters.

So, its area would be

A= w \times l = 10 \times 30 = 300 \ m^{2}

Therefore, the area of the parallelogram is 300 square meters. Its height (length) is 30 meters and its width is 10 meters.

3 0
4 years ago
Which logarithmic equation is equivalent to the exponential equation ?
Alika [10]
B. log2 8=c

Take log2 of both sides.
3 0
4 years ago
Answer correctly pls lol kk
Annette [7]

Answer: y= -4x-2

Step-by-step explanation:

glad i could help!

7 0
3 years ago
What is the difference between-5 and 2
Scorpion4ik [409]

Answer:

7

Step-by-step explanation:

Going from -5 to 2 we get

1) -4

2) -3

3) -2

4) -1

5) 0

6) 1

7) 2

So, in total, there are 7 numbers between -5 and 2

6 0
3 years ago
Find the sum of the convergent series. (round your answer to four decimal places. ) [infinity] (sin(9))n n = 1
Alexus [3.1K]

The sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

For given question,

We have been given a series \sum_{n=1}^{\infty}~(sin(1))^n

\sum_{n=1}^{\infty}~(sin(1))^n=sin(1)+(sin(1))^2+...+(sin(1))^n

We need to find the sum of given convergent series.

Given series is a geometric series with ratio r = sin(1)

The first term of the given geometric series is a_1=sin(1)

So, the sum is,

= \frac{a_1}{1-r}

= sin(1) / [1 - sin(1)]

This means, the series converges to sin(1) / [1 - sin(1)]

\sum_{n=1}^{\infty}~(sin(1))^n

= \frac{sin(1)}{1-sin(1)}

= \frac{0.8415}{1-0.8415}

= \frac{0.8415}{0.1585}

= 5.31

Therefore, the sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

Learn more about the convergent series here:

brainly.com/question/15415793

#SPJ4

7 0
1 year ago
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