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Virty [35]
3 years ago
10

The graph shows the relationship between the volume of a rectangular prism and the volume of a square pyramid with an identical

base and height.
A coordinate plane showing Prism versus Pyramid. The x-axis shows Pyramid Volume in cubic units and the y-axis shows Prism Volume in cubic units. The line starts at (0, 0) and passes through (1, 3), (2, 6) and (3, 9).

What is the slope of the line?

−3


3
Mathematics
2 answers:
san4es73 [151]3 years ago
5 0

Answer:

Its option D, 3

Step-by-step explanation: rise over run makes it 3/1

True [87]3 years ago
3 0

Answer: is it on chart? if count rise over run

Step-by-step explanation:

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Find the surface area of the solid. Round to two decimal places
Ne4ueva [31]
Check the picture below.

so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{34^2-22^2}=b\implies \sqrt{672}=b

so then the surface area of the triangular prism is,

\bf \stackrel{\textit{left and right}}{2(34\cdot 76)}~~+~~\stackrel{\textit{bottom}}{(44\cdot 76)}~~+~~\stackrel{\textit{front and back}}{2\left[\cfrac{1}{2}(44)(\sqrt{672})  \right]}
\\\\\\
8512~~+~~(44)(\sqrt{672})\qquad \approx\qquad 9652.61036291978

5 0
3 years ago
6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at
SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

\frac{dQ}{dt}= flow\ in - flow\ out\\ \\flow\ in=3\ gal/min*2\ lb/gal=6\ lb/min\\\\net\ gain\ in\ tank\ volume=3-4=-1, henceflow\ out= \frac{4Q}{100-t} \\\\\frac{dQ}{dt}= 6-\frac{4Q}{100-t} \\\\\frac{dQ}{dt}+ \frac{4Q}{100-t}=6\\\\The \ integrating\ factor\ is:\\\\IF=e^{\int\limits {\frac{4}{100-t} } \, dt }=e^{-4\int\limits {\frac{-1}{100-t}}=e^{-4ln(100-t)}=(100-t)^{-4}}\\\\Multiplying\ through  \ by\ IF: \\\\(100-t)^{-4}\frac{dQ}{dt}+ (100-t)^{-4}\frac{4Q}{100-t}=6(100-t)^{-4}\\\\

Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}

7 0
3 years ago
Which one of the following numbers will appear farthest to the left on a number line?Which one of the following numbers will app
Viefleur [7K]
-6.04 is the farthest left on a number line.

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4 years ago
a circle with radious of 1cm sits inside a 11cm times 12 cm rectangle what is the area of the shaded region
Nitella [24]

Answer: 128.86cm²

Step-by-step explanation:

The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.

Area of the rectangle                                  =  11 x 12

                                                                     =  132cm²

Area of the circle with radius of 1cm          =  πr²

                                                                     = 3.142 x 1²

                                                                     = 3.142cm²

Therefore , area of the shaded  region      = 132cm²  -  3.142cm²

                                                                    = 128.86cm²

7 0
3 years ago
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How do you simplify a fraction?
attashe74 [19]
You simplify a fraction by finding it's greatest common factor. A greatest common factor is what both numbers are divisible by. If they can both be divided by two, then you've simplified them a little bit. Keep going until you can't find a common number that can be divided by the two, and you've got your simplified fraction. For example, 10/5 = 1/2 since both 10 and 5 is divisible by 5.
5 0
3 years ago
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