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Leni [432]
3 years ago
10

Suppose that you draw two cards from a deck. After drawing the first card, you do not put the first card back in the deck. What

is the probability (rounded to the nearest ten thousandth) that both cards are diamonds?
(A) 0.0543
(B) 0.0588
(C) 0.0625
(D) 0.0643
(E) None of the above
Mathematics
1 answer:
S_A_V [24]3 years ago
8 0

Answer:

(B) 0.0588

Step-by-step explanation:

The probability is calculated as a division between the number of possibilities that satisfy a condition and the number of total possibilities. Then, the probability that the first card is diamonds is:

P_1=\frac{13}{52}

Because the deck has 52 cards and 13 of them are diamonds.

Then, if the first card was diamonds, the probability that the second card is also diamond is:

P_2=\frac{12}{51}

Because now, we just have 51 cards and 12 of them are diamonds.

Therefore, the probability that both cards are diamonds is calculated as a multiplication between P_1 and P_2. This is:

P=\frac{13}{52}*\frac{12}{51}=\frac{1}{17}=0.0588

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If her brother has 40 tickets, the equation will be 3(40)+2=122. jamie will have 122 tickets

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Step-by-step explanation:

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3 years ago
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Ivan and 3 acrobats are matched up against a team of grandma's. The result is a tie the 2 sides are evenly matched. How many gra
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Step-by-step explanation:

Ivan and 3 others were evenly matched.

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4 0
3 years ago
Pythagorean theorem in 3D
kiruha [24]

Answer:

d = 6.997 or 7

Step-by-step explanation:

Use Pythagorean Theorem to find the diagonal of the end of the prism

2^2 + 3^2 = C^2     Simplify

4 + 9 = C^2             Add

13 = C^2                  Take the square root of both sides

3.6 = C

Now plug this into the Pythagorean Theorem equation for the diagonal of the whole prism.

3.6^2 + 6^2 = d^2     Simplify

12.96 + 36 = d^2       Add

48.96 = d^2               Take the square root of both sides

6.997 = d                   This can be rounded up to 7, if needed

5 0
3 years ago
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
3 years ago
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