Answer:
F(d) = 30 + 0.50d
Step-by-step explanation:
Given
Charges = P8.00 ---- first 4 km
Additional = P0.50
Required
Write a function to address the scenario.
Represent the whole distance covered with d.
First,we need to determine the total charges for the first four hours.
Charges = 8.00 * 4
Charges = 32.00
Next, we determine the charges for additional distance.
Charges = 0.50 * (d - 4)
d - 4 is the remaining distance after the first 4.
Charges = 0.50d - 2
The function is then written as;
F(d) = 32 + 0.50d - 2
F(d) = 32 - 2 + 0.50d
F(d) = 30 + 0.50d
Answer:
f(x) = - 8
Explanation:
The given function is
f(x) =2x^2 -4x -6
The first step is to find the derivative of the function. Recall, if
y = ax^b
y' = abx^(b - 1)
Thus,
f'(x) = 4x - 4
We would equate f'(x) to zero and solve for x. We have
4x - 4 = 0
4x = 4
x = 4/4
x = 1
We would substitute x = 1 into the original function and solve for f(x) or y. It becomes
f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6
f(1) = - 8
Thus, the minimum value is f(x) = - 8
We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°
After 1 hours, the distance traveled by the ship is
dv = 18 mi
The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />
Add 9, 6 times
And add 8, 7 times
