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gayaneshka [121]
3 years ago
7

If the area of a square is 1 square meter, how many centimeters long is each side?

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

25 centimeters

Step-by-step explanation:

1 meter is 100 centimeters.

10 ÷ 4 = 25

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D because if you multiply y 8 times it will no longer be doubling the area
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Which property or properties of arithmetic do you use when you calculate 3×70 by first calculating 3×7 = 21 and then putting a z
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The property used is the Associative property

3 × 70 = 3(70) = 3 (7×10) = (3×7) ×10

The formula is

a × bc = a (bc) = a (b×c) = (a×b) ×c
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Read 2 more answers
Solve number 8 (geometry)
ANEK [815]

Answer:

x = 50

Step-by-step explanation:

the word bisects means that it cuts in half (this is how I understand it, not the official definition :D)

so that means

\angle XAB =\angle BAY\\\\2x=100\\\\x=50

3 0
3 years ago
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
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