All categories

2 years ago

Pls help ASAP will mark brainliest

Mathematics

1 answer:

wolverine [178]2 years ago

3 0

Answer:

Step-by-step explanation:

Rectangular prisms have F=6 faces and E=12 edges.

By cutting one corner, we are adding 3 edges.

By cutting two corners, we are adding 2*3 = 6 edges.

Therefore the new solid has 12 + 6 = 18 edges.

You might be interested in

Find the value of x. Enter your answer as a fraction.<br> 50 points asap!

Travka [436]

Answer:

3/2

Step-by-step explanation:

that is it. if u do ur measure correctly

3 0

2 years ago

What is the answer of:<br> z^2 - 4z^2

Novosadov [1.4K]

$z^2 - 4 z^2$

$z - 4z$

$= - 3 z^2$

hope this helps!.

4 0

2 years ago

Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

2 years ago

I<br> 1<br> 8 in<br> Find h.<br> 13 in<br> = √[?] in.

Archy [21]

as the following pic you can see the answer.

#diameter is 8 so radius is 4

8 0

1 year ago

find the two angles measures from the diagram 7x+9 5x+3 there's 3 answers 1. 73 and 73 2. 107 ,107 3.107 and 73 this is so confu

viva [34]

Answer:

Step-by-step explanation:

supplementary angle

7x + 9 + 5x + 3 = 180

12x = 180 - 3 - 9

x = 168 / 12

x = 14

plugin x=14 into the equation

= 7x + 9

= 7(14) + 9

= 107°

plugin x=14 into the equation

= 5x + 3

= 5(14) + 3

= 73°

4 0

2 years ago