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finlep [7]
3 years ago
5

Franado brought 8 pints of milk how many fluid ounces of milk did he by 1664128256

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0
To understand how many fluid ounces Franado has, we need to convert pints to fluid ounces. To do that, we need to determine how many fluid ounces are in 1 pint.

1 pint = 16 fluid ounces.
We have 8 pints. Let's multiply 16 by 8 to convert 8 pints to fluid ounces.
16(8) = 128.

There are 128 fluid ounces in 8 pints.
Your answer is C.) 128.

I hope this helps!
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Given: ∠AOC, ∠BOC - complementary angles
34kurt

Answer:

  • 30
  • COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

  AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

__

The second part of the previous statement is ...

  AOC + COB = 90

so we believe this (COB) should go in the second blank.

__

Then the line of interest would read ...

  BOC + 30 + COB = 90

_____

<em>Comment on the problem</em>

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

  BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to  BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

  m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

  (m∠BOC + 30°) + m∠BOC = 90° . . . . substitution for m∠AOC

  2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

  m∠BOC = 30° . . . . . . . . algebra (divide by 2)

3 0
3 years ago
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myrzilka [38]

Answer:

-7x^2+x+9=-6x

-7x^2+x+9+6x=-6x+6x

-7x^2+7x+9=0

quadratic\: formula

x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}

\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}

x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}

\frac{-7+\sqrt{301}}{2\left(-7\right)}

=\frac{-7+\sqrt{301}}{-2\cdot \:7}

=\frac{-7+\sqrt{301}}{-14}

\frac{-7-\sqrt{301}}{2\left(-7\right)}

=\frac{-7-\sqrt{301}}{-2\cdot \:7}

=\frac{-7-\sqrt{301}}{-14}

answer=\frac{7+\sqrt{301}}{14}

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by-step explanation:

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