One bag would be 2.7 kg. If you equally pour 8 kg of oats into 3 bags, you divide 8 by 3 which gets you 2.666666666666667 (rounded to one decimal place is 2.7, it depends to what decimal place the question asks you to round your answer to).
The equation r = square root of theta can be translated into a semi-circle through the simplification to r^2 = theta. When theta is 0, r is zero. When r is -3pi/2, r2 is equal to 9/4 pi^2. The area of the semi-circle is equal to pi r^2 /2. Hence the area is equal to 34.88 units^2
Answer: 43 squared units
Explanation:
So the area is the total amount of the inside of the polygon (I’m not good at explaining) and you get your area from using measurements on the sides of the shape for example for a square let’s say the side is 4 and another side is 4 so you multiply that and you get 16 which is the area
So basically since this one is a open polygon you can just count the inside of the poly using the squares
Sum/difference:
Let

This means that

Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get

if again we assume x to be rational, we have

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
Answer:
B) no, because the corresponding angles are not congruent
Step-by-step explanation:
Similar triangles must have proportional sides, as well as congruent corresponding angles. In this instance, we can see that the angles are not <em>congruent</em>, and so there is no need to solve for proportion.
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