Answer:
B.
Step-by-step explanation:
Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Step-by-step explanation:
Suppose that the carrying capacity is 900 fish, the intrinsic growth rate is equal to 2, and the harvest rate is 20%.
a. Use the graphical or eigenvalue approach
Answer:
The first equation must be multiplied by 18 and second equation must be multiplied by 8
Step-by-step explanation:
This is similar to the other question you posted. Follow the same steps as before.
First find g(41).
g(41) = sqrt{x - 5}
g(41) = sqrt{41 - 5}
g(41) = sqrt{36}
g(41) = 6
We now find f(6).
f(6) = -7(6) + 1
f(6) = -42 + 1
f(6) = -41
Answer:
(fºg)(41) = -41
Did you follow?
