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Anastasy [175]
3 years ago
5

Starting from 300 feet away, a car drives toward you. It then passes by you at a speed of 48 feet per second.The distance d (in

feet) of the car from you after t seconds is given by the equation ​d=|300−48t|​. At what times is the car 60 feet from you?​
Mathematics
1 answer:
Sergio [31]3 years ago
4 0
About 2 seconds away from you
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Simplify using the order of operations. please show your math work step by step.
Dimas [21]

Answer:

23

Step-by-step explanation:

3 * [2 + (12 - 2 * 4)] + 5

~Multiply whats in parenthesis

3 * [2 + (12 - 8)] + 5

~Subtract whats in parenthesis

3 * [2 + (4)] + 5

~Add whats in brackets

3 * 6 + 5

~Multiply

18 + 5

~Add

23

Best of Luck!

4 0
3 years ago
Write an equation in point slope form of the line that passes through the given point and the given slope m
victus00 [196]

Answer:

The answer is

\huge y - 8 =  4(x + 9) \\

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

From the question we have the final answer as

y - 8 =   4(x + 9)

Hope this helps you

3 0
3 years ago
In the figure below AC and BE are diameters of circle P. what is the arc measure of DBE in degrees
Paraphin [41]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Saturn is 8.867 × 10^8 miles away from the Sun. Uranus is 1.787 × 10^9 miles away from the Sun. Approximately how many times far
Over [174]

Answer:

<em>2 times </em>

<em></em>

Step-by-step explanation:

Please refer to the image attached of our <em>solar system </em>in which Saturn and Uranus are clearly visible.

Distance of Saturn from Sun, D_{1} = 8.867 \times 10^{8}\ miles

Distance of Uranus from Sun, D_{2} = 1.787 \times 10^{9}\ miles

We have to find, how many times the Uranus is far from Sun than Saturn is far from Sun.

Let us begin by multiplying the distance of Saturn from Sun by 2: D_{1} \times 2 = 8.867 \times 10^{8}\ miles \times 2\\\Rightarrow 17.734 \times 10^{8}\ miles\\\Rightarrow 1.7734 \times 10^{1} \times  10^{8}\ miles\\\Rightarrow 1.7734 \times 10^{8+1}\  miles\\\Rightarrow 1.7734 \times 10^{9} $\approx$ D_{2}

From above, we can say that D_{2} is approximately <em>twice </em>of D_{1}.

In other words, we can say that Uranus is at approximately twice distance from Sun than that of Saturn is.

3 0
3 years ago
In circle D, which is a secant? Geometry pls answer!!!
Inessa [10]
I believe line G_H is a secant.
4 0
3 years ago
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