Speak in English please. I would be more pleased to help if you write in English.
The most ancient mathematical texts came from mesopotamia and Egypt. The “inventors” of math are the Greek beginning in around the 6th century BC.
Not sure if your trying to solve for x or v
Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Give a reason for each step of the proof.
Given: <1 and <2 are complimentary
<1 is congruent to <3,
<2 is congruent to <4
Prove: <3 and <4 are complimentary
Statements: Reasons:
1. <1 and <2 are complimentary 1.Given
2. m<1 + m<2=90* 2.<u>DEFINITION OF COMPLEMENTARY ANGLES</u>
3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______
4. m<1=m<3, m<2=m<4 4.<u>DEFINITION OF CONGRUENT ANGLES_</u>
5. m<3 + m<2=90* 5. <u>SUBSTITUTION PROPERTY (m<1 is replaced by m<3.) </u>
6. m<3 +m<4=90* 6. <u>DEFINITION OF COMPLEMENTARY ANGLES </u>
7. <3 and <4 are complimentary 7.<u> DEFINITION OF COMPLEMENTARY ANGLES</u>