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Tema [17]
3 years ago
13

Marco and Drew stacked boxes on a shelf. Marco lifted 9 boxes and Drew lifted 14 boxes. The boxes that Drew lifted each weighed

8 lb less than the boxes Marco lifted. Let m represent the weight of the boxes that Marco lifted.Which expression represents the total number of pounds Drew lifted?14(m−8)112m9(m+8)m−8
Mathematics
2 answers:
zubka84 [21]3 years ago
6 0
We let m be the weight of the boxes Marco lifted. From the problem statement, each box that Drew lifted is eight pounds less than Marco's boxes. It can be represented by (m-8). To find for the total number of pounds Drew lifted, we multiply the expression above by the number of boxes he lifted which is 14. Therefore, the correct answer is option B, 14(m-8).<span>
</span>
andre [41]3 years ago
3 0

if m = weight of boxes and the boxes drew lifted were 8 pound less you would have (m-8)

 Marco lifted 14 boxes so the equation would be 14(m-8)

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F(-x) = 2/-x/ + 3(-x) = 2/x/ - 3x;
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The number 40 cannot be decomposed into prime factors<br><br>True<br>either<br>False​
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\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\large{\textsf{\textbf{\underline{\underline{Answer : \:}}}}}}

False, because the number 40 is a composite number, those that cannot be broken down are called Prime Numbers.

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What is the verbal expression for 6f^2+5f
pychu [463]

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Step-by-step explanation:

5 0
2 years ago
Assume that blood pressure readings are normally distributed with a mean of 115 and a standard deviation of 8. If 100 people are
Sergeu [11.5K]

Answer:

D. 0.9938.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 115 and a standard deviation of 8.

This means that \mu = 115, \sigma = 8

100 people are randomly selected

This means that n = 100, s = \frac{8}{\sqrt{100}} = 0.8

Find the probability that their mean blood pressure will be less than 117.

This is the p-value of Z when X = 117, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{117 - 115}{0.8}

Z = 2.5

Z = 2.5 has a p-value of 0.9938, and thus, the correct answer is given by option D.

8 0
3 years ago
Need simplified please
Romashka-Z-Leto [24]

Answer:

70

Step-by-step explanation:

7^2 - ( 6-3^3)

PEMDAS

Parentheses first

7^2 - ( 6-3^3)

The exponent in the parentheses first

7^2 - ( 6-27)

7^2 - ( -21)

Now the exponent

49 - (-21)

Now subtract

49 +21

70

6 0
3 years ago
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