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djverab [1.8K]
4 years ago
8

Eric practiced piano and guitar for a total of 8 hours this week. He practiced the piano for 1/4 of that time. How many hours di

d Eric practice the piano this week?
Mathematics
1 answer:
Oduvanchick [21]4 years ago
5 0

Answer:

I don’t know

Step-by-step explanation:

I said idk

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Firstly
Murljashka [212]

Answer:

a=3 IF it's continuos

Step-by-step explanation:

for continuity, the left limit of the first equation must be equal to the right limit of the third equation

and they are equal, as you can see putting x=2 in both equations

to be continuos in a point c, f(x) must:

be defined in c (so f(c) exists)

the limit in c exists (in this case both from left and right)

the limit in c must be equal to f(c)

5 0
3 years ago
In the figure, angle B measures 44°, angle A measures 62°, and angle E measures 50°.
Gre4nikov [31]
We don't need the figure
angle b = 44 degrees
angle a = 62 degrees
angle e = 50 degrees
angle f = unknown
we know that 
angle a + b + e + f = 180 degrees
50 + 44 + 62 + f =180 degrees
f= 180-50-44-62
but here there is only one blank so we have to add 44 and 62 to make one number that is 106
therefore, f = 180-50-106
if you further want to solve it angle f is 24
3 0
3 years ago
Please help me with 5
Solnce55 [7]
3/5 times 1100= 660
1100-660= 440
440 times .70 = 308
440-308= 132 fish were not bluegill or catfish
4 0
3 years ago
The total area of Fred's yard is 60 square feet. The length is 6 feet. What is the width?
inysia [295]

Answer:

Step-by-step explanation:

<h2>             </h2>
7 0
3 years ago
Read 2 more answers
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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