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Juli2301 [7.4K]
3 years ago
12

6/7 times 4/5 times 35

Mathematics
2 answers:
scoray [572]3 years ago
8 0
That is so easy :)
the answer is 24
DochEvi [55]3 years ago
6 0
Hi there!

This is very easy and could be done on a calculator.

(6/7(4/5)) (35)
= 6/7 (4/5) (35)
= 24/35 (35)
= 24

Hope this helped!
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kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

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Please Help ASAP
Tju [1.3M]

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The discriminant is ...

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A negative discriminant means there are no real solutions to the equation.

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The complex solutions are 1±i√7.

If we assume the equation has a typographical error and is intended to be ...

  2x^2 -4x -16 = 0

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3 years ago
In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer
soldi70 [24.7K]

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

T_n=ar^{n-1}

Here, n =12

So,

T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1

or

T_{12}=53144

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3 years ago
What is the answer to 5(–2 − 4d) =
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5 0
2 years ago
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Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0
BartSMP [9]

The power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}

We can write g(x) as,

\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\

We know that, \frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n} if |x| < 1

and \frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n  if |\frac{x}{6}| < 1

\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\     if |x| < 1 and  if |\frac{x}{6}| < 1

\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n) if |x| < 1

Therefore, the power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0
2 years ago
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