Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Ok let's do this*pops knuckles*
let's add the first side

order of operations demands that we do multiplication first(P.E.M.D.A.S)
so

now we can add the 1 from

into our six

now we substract

now we have

now we focus on the
other side

since 5 is in paranthesis we use something called the distributive property. it mean we will multiply the 5 by both of the 2.

now we have

(the three is from the original equation)
now we plug in our final numbers

or

I hope this helps
Answer:
Option B - graphing is the correct answer.
Step-by-step explanation:
To solve a system of inequalities we need graphing. Inequality tells us about the relative size of two values. When we graph the x and y co-ordinates, the solution is not the drawn line, but the area of the coordinate plane that satisfies the inequality. In inequalities, multiple solutions can be possible.
Plug and chug method does not a complete solution, it only tells where a point belongs. Guess and check does not apply here.
Answer:
Hi I only know part be yes the figures are congruent
Step-by-step explanation:
There the same shape, same size so yes they are congruent