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prisoha [69]
4 years ago
5

Solve x2 – 8x + 41 = 0 for x.

Mathematics
2 answers:
BARSIC [14]4 years ago
7 0

The equation x^2-8x+41=0 is quadratic equation that requires finding discriminant

D=b^2-4ac=(-8)^2-4\cdot 41=64-164=-100.

Since discriminant is negative, this equation has two complex roots. Note that -1=i^2, where i is imaginary unit. Then D=-100=100\cdot (-1)=100\cdot i^2,\\ \\\sqrt{D}=10i.

Now the complex roots are

x_1=\dfrac{8+10i}{2}=4+5i,\\ \\x_2=\dfrac{8-10i}{2}=4-5i.

Answer: correct choice is D.

iren [92.7K]4 years ago
4 0

Answer:

x+4+-5i

Step-by-step explanation:

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