Answer:
C
Step-by-step explanation:
(2x + 3)^5 = C(5,0)2x^5*3^0 +
C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5
Recall that
C(n,r) = n! / (n-r)! r!
C(5,0) = 1
C(5,1) = 5
C(5,2) = 10
C(5,3) = 10
C(5,4) = 5
C(5,5) = 1
= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5
= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243
= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243
= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243
180-55-39=86
x=86
Hope it helps
2a.) 8.8 x 4 = 35.2g
2b.) 35.2 x 30 = 1056g or 1.056kg
7/2= radius (3.5)
V=πr2^<span>h
V=</span><span>π3.52*12
V= 461.81 </span>
Solution: We are given the population mean 
Now, in order to find which shift's mean is closest to population mean, we will find the mean of each shift.
The mean of shift 1 is:

The mean of shift 2 is:

The mean of shift 3 is:

The mean of shift 4 is:

We clearly see the mean of shift 2 is close to the population mean. Hence the option B) Shift 2 is correct.