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3 years ago

12

PLEASE ANSWER IF YOU CAN!

1 answer:

anzhelika [568]3 years ago

4 0

Part A you will have to draw.
Part B:
Smithon to Hedgeborough: 2.5
Smithon to East Bunting: 3
Hedgeborough to East Bunting: -0.6

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Determined to find the slope<br>(1 7K), and (-3,5K)

Helga [31]

Answer: $\dfrac{K}{2}$ .

Step-by-step explanation:

As we know ,

The slope of a line that passes through $(x_1,y_1)$ and $(x_2,y_2)$ is given by :

$\dfrac{y_2-y_1}{x_2-x_1}$

The slope of a line that passes through (1 , 7K), and (-3,5K) =

$\dfrac{5K-7K}{-3-1}\\\\=\dfrac{-2K}{-4}\\\\=\dfrac{K}{2}$

Hence, the slope of the given line is $\dfrac{K}{2}$ .

8 0

2 years ago

NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH

lesya692 [45]

$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

<u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

$\bold{\underline{To \: Find :- }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

<u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

$\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}$

$\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}$

$\sf{Distance\:GH=√(-8)^2+(12)^2}$

$\sf{ Distance \:GH =√64 + 144 }$

$\sf{ Distance \:GH =√ 208}$

$\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}$

$\sf{ Distance \:GH = 4√13}$

$\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}$

3 0

2 years ago

I need your help on this one pls its another one but different question<br> and please dont guess

Ainat [17]

Answer:

All except the second one (angle g is not similar to angle r)

Step-by-step explanation:

Just look at the order of the letters. It it's the same, its similar.

4 0

3 years ago

PSYCHO15rus [73]

Answer:

A

Step-by-step explanation:

The first one is -2x + 3

The seconf one is -2x +7

Look, same slope.

7 0

1 year ago

9.72÷9 ___________________

goldenfox [79]

Answer:

1.08

9.72 / 9 = 1.08

8 0

3 years ago

Read 2 more answers