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2 years ago

Please help it’s a timed exam

Mathematics

1 answer:

lina2011 [118]2 years ago

7 0

Answer:

Here 86 is answer.

So you better choose 86.

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Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)

Gnom [1K]

Answer: Horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

Step-by-step explanation:

Since we have given that

$y=\dfrac{x^2-9}{4x^2+1}$

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

Now,

$4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}$

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

$y=\dfrac{1}{4}$

Hence, horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

8 0

2 years ago

Solve the following equation x+2=10

Maru [420]

Answer:

x=8

Step-by-step explanation:

8 0

3 years ago

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Please help meeeee! <br> I'm really in a rush rn!

yawa3891 [41]

Answer:

-3.392

Step-by-step explanation:

2.34

1.052

+_____

= 3.392

3 0

2 years ago

What do you know to be true about the values of p and q?

artcher [175]

Answer:

p = q

Step-by-step explanation:

Angles in a triangle add up to 180°

For the left triangle:

180 = p + 20 + 80

p = 80

For the right triangle:

180 = q + 45 + 55

q = 80

Therefore, p = q

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2 years ago

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If f(x)=-2x^2+5x-3 and g(x) is the reflection of f(x) across the y-axis, then an equation of g is which of the following

Ymorist [56]

To reflect a function across the y-axis you have to change

$x\mapsto -x$

So, the function becomes

$f(x)=-2x^2+5x-3 \mapsto f(-x)=-2(-x)^2+5(-x)-3=-2x^2-5-3$

3 0

3 years ago