Answer:
40,320
Step-by-step explanation:
He can pick any one of the eight for the first examination.
He can pick any one of the remaining 7 for the 2nd examination.
He can pick any one of the remaining 6 for the 3rd examination.
...
He can pick any one of the remaining 2 for the 7th examination.
There's one left for the 8th examination.
Thus, there are 8×7×6×5×4×3×2×1 = 8! = 40,320 different possible orders in which the tubes can be examined.
The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
31.4
Step-by-step explanation:
So a really easy way to solve this is as goes
--> 3.14 x (20 x 1/2)
--> 3.14 x (10)
Now multipling by 10 is just moving the deciaml place one spot to the right
=> thus, we get 31.4
Hope this helps!
Answer:
22 weeks
Step-by-step explanation:
