$\bf 2=x^2+5x\implies 0=x^2+5x-2\\\\\\\qquad \qquad \qquad \textit{discriminant of a quadratic}\\\\\\0=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+5}x\stackrel{\stackrel{c}{\downarrow }}{-2}~~~~~~~~\stackrel{discriminant}{b^2-4ac}=\begin{cases}0&\textit{one solution}\\positive&\textit{two solutions}\\negative&\textit{no solution}\end{cases}\\\\\\(5)^2-4(1)(-2)\implies 25+8\implies 33$

so we have a 33, namely two real solutions for that quadratic.

usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.

so 33 can only afford us two real irrational roots.

3 0

3 years ago

The length of a rectangle is x² + 6x + 3 and the width is 3x² + 4x - 2. Which expression represents the are of the rectangle

miss Akunina [59]

Answer:

Step-by-step explanation:

area of rectangle=length×width

=(x²+6x+3)×(3x²+4x-2)

=3x^4+(4+18)x³+(-2+24+9)x²+(-12+12)x-6

=3x^4+22x³+31x²-6

7 0

3 years ago