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MakcuM [25]
3 years ago
5

How to solve this algebraically?

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
Ok so x+4-1 makes x-1 so i belive the answer could be 1/5 
laila [671]3 years ago
7 0
I believe in order to solve this question, use L'Hopital's Rule, as both the top and bottom will equal 0/0. Which is not what we want. Basically take the derivative of the top expression and take the derivative of the bottom expression. So the derivative of top can be written as d(X)/dx - d(5)/dx and divide everything by the derivative bottom expression that you must take as d(X+4)^1/2/dx, as square root of X+4 is the same as (X+4)^1/2. So altogether it would be d(X+4)^1/2/dx - d(3)/dx. So after taking the derivative on the top it becomes 1-0= 1. Then taking the derivative of bottom will be 1/[2(X+4)^1/2] - 0 = the same thing. Plugging in 5 into the new expression with derived top and bottoms would be 1/1/[2(5+4)^1/2. Evaluating will give you the answer as 1/6.
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Please help with problems 6 and 7.
monitta
6 is A and seven is B
7 0
3 years ago
Shopping at Savers Mart, Lisa buys her children 4 shirts and 3 pairs of pants for $85.50. She returns the next day and buys 3 sh
maria [59]

Answer:

price for one shirt

=

$

7.50

price for one pair of pants

=

$

18.50

Explanation:

Start by letting variables

x

and

y

represent the pieces of clothing from the problem.

Let

x

be the price of one shirt.

Let

y

be the price of one pair of pants.

Equation

1

:

4

x

+

3

y

=

85.50

Equation

2

:

3

x

+

5

y

=

115.00

You can solve for each variable by using elimination or substitution. However, in this case, we will use use elimination. First, we will solve for

y

, the price of each pair of pants.

To isolate for

y

, we must eliminate

x

. We can do this by making the two equations have the same

x

values. First, we find the LCM of

4

and

3

, which is

12

. Next, multiply equation

1

by

3

and equation

2

by

4

so that

4

x

and

3

x

becomes

12

x

in both equations.

Equation

1

:

4

x

+

3

y

=

85.50

3

(

4

x

+

3

y

)

=

3

(

85.50

)

12

x

+

9

y

=

256.50

Equation

2

:

3

x

+

5

y

=

115.00

4

(

3

x

+

5

y

)

=

4

(

115.00

)

12

x

+

20

y

=

460.00

Now that we have two equations with

12

x

, we can subtract equation

2

from equation

1

to solve for

y

.

12

x

+

9

y

=

256.50

12

x

+

20

y

=

460.00

−

11

y

=

−

203.50

y

=

18.50

⇒

price for one pair of pants

Now that we know that a pair of pants is

$

18.50

, we can substitute this value into either equation

1

or

2

to find price for one shirt. In this case, we will choose equation

1

.

4

x

+

3

y

=

85.50

4

x

+

3

(

18.50

)

=

85.50

4

x

+

55.5

=

85.50

4

x

=

28

x

=

7.50

⇒

price for one shirt

∴

, the price for one shirt is

$

7.50

and the price for one pair of pants is

$

18.50

.

Step-by-step explanation:

yea

5 0
3 years ago
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