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sukhopar [10]
3 years ago
7

The value of (a–1)+92 - +24,5 " when a= 2 and b=-1

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

256271

Step-by-step explanation:

6165253-6728282-289292

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Which equation has the following characteristics?
leva [86]
Answer is B. Have a nice day.
5 0
3 years ago
Find the slope of the line that passes through the given points.<br> (-5,6) and (2,6)
CaHeK987 [17]

Answer:

0

Step-by-step explanation:

Your slope would be 0. To find the slope of a line given two points, you find the change in y over the change in x.

In this case, the change in y was 6 - 6 which equals 0.

The change in x was -5 - 2 which was -7.

Since your numerator is 0, 0 divided by anything is automatically equal to 0 no matter what the denominator is.

Therefore, your answer would be 0.

I hope this helped :)

7 0
3 years ago
Find each one of the indicated angle measures.
PtichkaEL [24]

Answer:

∠5 = 71° & ∠8 = 109°

Step-by-step explanation:

∠1 = ∠5 (corresponding angle)

∠5 = 71°

∠5 + ∠8 = 180° (angles in a striaght line is 180°)

71° + ∠8 = 180°

∠8 = 109°

7 0
3 years ago
With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
Given z1 and z2 below. Calculate z1/z2 and write your answer in rcistheta form.
andre [41]

Answer:

  (2/9)cis(30°)

Step-by-step explanation:

We can express the two numbers in magnitude∠angle form, then find their ratio.

  |z1| = 3√((-1)² +(√3)²) = 3√4 = 6

  ∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

  z2 = 27∠90°

So, the ratio is ...

  z1/z2 = (6∠120°)/(27∠90°) = (6/27)∠(120°-90°)

  z1/z2 = (2/9)∠30°

8 0
3 years ago
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