Y = mx + b
slope(m) = 6
(-3,5)...x = -3 and y = 5
now we sub and find b, the y int
5 = 6(-3) + b
5 = -18 + b
5 + 18 = b
23 = b
so ur equation is : y = 6x + 23
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
Your answer is 45.. I am 100% positive
Answer:
Option A.
Step-by-step explanation:
Distance between Bob and the center of the mountain at the base = 19,427.5 ft.
Angle of elevation to the top of the mountain = 25°11'
We know that
1 degree = 60 minutes
1/60 degree = 1 minute

Let the height of the mountain be h.
In a right angled triangle






Therefore, the height of the mountain to the nearest foot 9135. Option A is correct.